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I was very happy & proud when I solved that problem some 5 years ago (found the first move), then another one and made some small error some 20 moves later.
Posts: 2011 Location: Groningen, NL Liked others: 202 Was liked: 1087
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Araban wrote:
Those who are up for a challenge may want to consider this slightly different problem (also cut away the excess from Kirby's problem with a shorter ladder-breaker). The thing about the problem posted by Kirby is that E13 is suboptimal play from White in response to Black E14:
[go]$$Bcm1 $$ ------------------------- $$ | . . . . . . . . . . . . $$ | . . O O . . . O O . . . $$ | . . O X X X X X O . O . $$ | . . . O O O X O X X . . $$ | . . . . X X O O . . . . $$ | . . . . 1 8 3 4 7 X . . $$ | . . . 2 x 9 6 5 . . . . $$ | . . . . . . . . . . O . $$ | . . . . . . . . . . . .[/go]
Ko.
at x, as Kirby has it, is much harder to punish, but if punished correctly leads to unconditional capture of the white stones. This is also a double ladder breaker, but it only gives black a ko, instead of an unconditional kill
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Tommie
at x, as Kirby has it, is much harder to punish, but if punished correctly leads to unconditional capture of the white stones. This 
at 
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