That's what current Japanese rules do. OC, White can reopen play. Black will have the move, but will pass, and then White will play and get 3 pts.RobertJasiek wrote:In your three-points-without-capturing shape, scoring rules can define whatever score to the initial position... So if the scoring rules are CGT territory scoring defined for terminal positions, the score and therefore counts of the black and white terminal followers are -5 and -3, respectively. So in CGT the initial position's count is -3.
You suggest that other scoring rules could score the initial position as 0, but why 0?
Plainly they do when b = w = m, where m is the mean value. We just do not call them double sente.I am still trying to understand whether a local double sente with b <= w exists.
By "sente sequence" I just mean a sequence that is played with sente. The original position may be a gote.With "sente sequence", I think you do not just mean an alternating 2-play sequence but additionally presume a requirement of it belonging to a simple sente.
Every line has an equation. The axes are v (for value) and t (for temperature), if you will. For the line, v = x, x is the intercept on the v axis.I do not exactly understand the annotation v = x yet. Is this an abbreviation for v(t) = x, with t >= 0 being the temperatures? I.e., v is a mapping (abbildung)?
We do not have to calculate a mean value, m. We only have to know that one exists, and that it is calculable. (See ONAG.)So this is just a sketch of what must be worked out as a proof in detail.
Part I: We have to calculate the mean value. Since it is defined for some multiple of the local endgame, we have to study multiples of it until we find a suitable number of multiples of it to get the mean value.
In the case of an apparent double sente, we also have to know that b >= m >= w. If it is really a double sente, then m is incalculable.
Edit: Here is a true double sente where b > w.
Code: Select all
D
/ \
/ \
E F
/ \ / \
∞ b w -∞
OC, D does not have a mean value.