oca wrote:
I tryied that one but didn't liked
$$W
$$ | . . c O . . . . . . .
$$ | . O . . . . . . . . .
$$ | . O X X a . . . . , .
$$ | X X 2 . 3 X . O . . .
$$ | . O 4 1 . b . . . . .
$$ | . . . . . . . . . . .
$$ -----------------------
- Click Here To Show Diagram Code
[go]$$W
$$ | . . c O . . . . . . .
$$ | . O . . . . . . . . .
$$ | . O X X a . . . . , .
$$ | X X 2 . 3 X . O . . .
$$ | . O 4 1 . b . . . . .
$$ | . . . . . . . . . . .
$$ -----------------------[/go]
but seems we cannot have it all....
If by all you mean kill every black stone, then yes that's an unreasonable expectation of a fair outcome for you.

But that above diagram is already REALLY good for white and in fact black isn't even alive in the corner and he might even die, so you might get it all after all! Btw 4 is a mistake, black should play
a and white answers at
b to get out into the centre*, then playing at 4 might be good (but probably not) or some move on the outside. If black plays 4 immediately white is happy to play
a.
*(for more advanced players) black at
a is not the only choice here and exchanging for b could be a bad exchange due to other options using the aji at
c. Particularly if black wedged instead of connect for 2 then this sort of variation looks interesting (so maybe white won't cut at 7 but answer on 2nd line to avoid giving black 8 and 10 in sente, but then he has other problems, depends on left side). If black resistances like this are effective then perhaps white should play 5 at
b directly.
$$W
$$ | . . 9 a . . . . . . .
$$ | . . 6 O 0 . . . . . .
$$ | . O 7 8 . . . . . . .
$$ | . O X X . . . . . , .
$$ | X X 4 . 5 X . O . . .
$$ | . O 2 1 . b . . . . .
$$ | . . 3 . . . . . . . .
$$ -----------------------
- Click Here To Show Diagram Code
[go]$$W
$$ | . . 9 a . . . . . . .
$$ | . . 6 O 0 . . . . . .
$$ | . O 7 8 . . . . . . .
$$ | . O X X . . . . . , .
$$ | X X 4 . 5 X . O . . .
$$ | . O 2 1 . b . . . . .
$$ | . . 3 . . . . . . . .
$$ -----------------------[/go]