Life In 19x19

Posted: **Sun Mar 20, 2016 9:38 pm**

Hi, I have a question about a diagram showing how to utilize a shortage of liberties (Diagram 33-3 in An Encyclopedia of Go Principles by Richard Bozulich)

The first diagram shows how if white tries to link its stones, black can use 3 to prevent it.

Click Here To Show Diagram Code: [go]$$Bc $$ +---------------------------------------+ $$ . . . . . 6 . . . . | $$ . . . 5 2 3 4 O . . | $$ . . O 7 X O O X X . | $$ , . . . . X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . | $$ . . . . . . . . . . | $$ . . . . . . . . . . |[/go]

What I'm wondering is why white can't atari with six instead of capturing, as in the second diagram. It seems to me that if black plays on the red circle, white could capture black 3. Or if black captures white 2, white could play on the black circle. I can't find a sequence where black can prevent white from linking up. I'm still pretty new to the game, so I imagine it is fairly obvious, but I've gone over it many times and I still can't see it. Thanks.

Click Here To Show Diagram Code: [go]$$Bc $$ +---------------------------------------+ $$ . . . . . . . . . . | $$ . . . 5 2 3 4 O . . | $$ . . O 6 X O O X X . | $$ , . . . C X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . | $$ . . . . . . . . . . | $$ . . . . . . . . . . |[/go]

Posted: **Mon Mar 21, 2016 12:10 am**

Click Here To Show Diagram Code: [go]$$Bc $$ +---------------------------------------+ $$ . . . . 7 . . . . . | $$ . . . 5 9 3 4 O . . | $$ . . O 6 X O O X X . | $$ , . . . 8 X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . | $$ . . . . . . . . . . | $$ . . . . . . . . . . |[/go]

And then?

Posted: **Mon Mar 21, 2016 1:04 am**

Hi sigger,

Continuing from Kirby's

connect in post 2:

If

first turns on the left, W dies:

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . 5 . X . . 6 . . | $$ . . 1 X X X O O 4 . | $$ . . O O X O O X X . | $$ , . . 3 O X X . . . | $$ . . O . 2 . . X . . | $$ . . . . . . . . . . |[/go]

However:
If

extends first on the right, it gets tricky:

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . . . X . . . . . | $$ . . . X X X O O 1 . | $$ . . O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

For example:

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . 7 . X . 5 . 4 . | $$ . . 3 X X X O O 1 2 | $$ . . O O X O O X X 6 | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

Or:

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . . . X . . . . . | $$ . . 2 X X X O O 1 . | $$ . . O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

There are a few variations.

If the original position has an extra black stone

,
it would simplify things -- I wonder if it's OK --

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . . . . . . . . . | $$ . . . . 1 . . O B . | $$ . . O . X O O X X . | $$ , . . . . X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

sigger wrote:I'm still pretty new to the game, so I imagine it is fairly obvious,

sigger, this is not an obvious position for beginners,
especially with the original Diagram in post 1.

Posted: **Mon Mar 21, 2016 1:33 am**

Posted: **Mon Mar 21, 2016 1:43 am**

schawipp wrote:white will finally die in the corner.

Hi schawipp, if it works out for black, good.

It seems about 15 moves of reading from the original diagram -- how would you approach this when explaining to a beginner ?
Quite a few variations; I don't have the source book --
I don't know what's shown and which variations are omitted.
And how do you feel about having an extra black stone at S18 in the original set-up ? Good, neutral, bad -- concerning the intent and clarity of this problem ?

Posted: **Mon Mar 21, 2016 2:12 am**

EdLee wrote:And how do you feel about having an extra black stone at S18 in the original set-up ? Good, neutral, bad -- concerning the intent and clarity of this problem ?

Bad, because it makes Black's play sente to kill. You want to show that the Black sequence is good, even if it is gote.

It is not easy to construct good examples.

Edit: Maybe better?

Click Here To Show Diagram Code: [go]$$Wc $$ ----------------------- $$ . . . . . 5 . . . . . . $$ . . . 4 1 2 3 O . . . . $$ . . O 6 X O O X X . X . $$ . . . . . X X . . . . . $$ . . O . . . . X . . . . $$ . . . . . . . . . . . . $$ . . . . . . . . . . . . $$ . . . . . . . . . . . .[/go]

Posted: **Mon Mar 21, 2016 2:16 am**

Bill Spight wrote:It is not easy to construct good examples.

Hi Bill, yep; thanks.

Posted: **Mon Mar 21, 2016 2:49 am**

sigger wrote: What I'm wondering is why white can't atari with six instead of capturing, as in the second diagram.

Well done for considering a white resistance. It's important when reading to not be self-indulgent and only look at the moves you want your opponent to play, but the tricky other choices they may have. Even if that tactic doesn't work in this example (was the edge of the board exactly as shown in your diagram?), in some shapes that white counter atari is indeed a clever tactic that works to stop black from cutting successfully, so it's good to be aware of it and you should read to make sure it doesn't work before embarking on this sequence. So I suppose a possible exercise is: can you construct a position in which that white counter atari does work to thwart black's plan?

Posted: **Mon Mar 21, 2016 5:53 am**

Hi EdLee,

EdLee wrote:how would you approach this when explaining to a beginner?

Yep, that is probably not the most beginner-friendly example.

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . . . X . . . . . | $$ . . . X X X O O . . | $$ . . O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

First I would try to guide a beginner to the above given position and show that the black stones have 4 effective liberties (i.e. it takes 4 moves to capture them without black answering) while the white stones have only 3. This should already ring the alarm bell for white. It can be easily demonstrated that white cannot just start capturing black:

Click Here To Show Diagram Code: [go]$$Wcm1 $$ --------------------- $$ . . 3 . X . . 4 . . | $$ . . 1 X X X O O 2 . | $$ . . O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

For a very first beginner I would stop here try to say that - when in doubt - it is at least helpful to count effective liberties. This may still fail due to special tactical issues in 10% of the cases but it's better than nothing.

So white should rather increase his own liberties first, but black can do the same and has more room for this. The following explanation is probably beyond beginner level:

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . 6 4 . X . 5 . . . | $$ a 2 3 X X X O O 1 . | $$ . b O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

Now, regardless whether w plays (a) or (b) black gets into some kind of ladder where black has one liberty too much (very bad idea for w) or black increases his liberties by walking along the 2nd line (in very bad shape, and white gets a strong 3rd line wall, but well...). Nevertheless, even without the additional "double threat" tactical issue, white cannot win this semeai.

Of course this may change if there are more white stones nearby at left side, but since the diagram stops here I assume that it's empty there

.

Posted: **Mon Mar 21, 2016 7:04 am**

EdLee wrote:Hi sigger,
Continuing from Kirby's connect in post 2:

If first turns on the left, W dies:
$$W
$$ ---------------------
$$ . . 5 . X . . 6 . . |
$$ . . 1 X X X O O 4 . |
$$ . . O O X O O X X . |
$$ , . . 3 O X X . . . |
$$ . . O . 2 . . X . . |
$$ . . . . . . . . . . |
Click Here To Show Diagram Code
[go]$$W $$ --------------------- $$ . . 5 . X . . 6 . . | $$ . . 1 X X X O O 4 . | $$ . . O O X O O X X . | $$ , . . 3 O X X . . . | $$ . . O . 2 . . X . . | $$ . . . . . . . . . . |[/go]
However:
If extends first on the right, it gets tricky:
$$W
$$ ---------------------
$$ . . . . X . . . . . |
$$ . . . X X X O O 1 . |
$$ . . O O X O O X X . |
$$ , . . . O X X . . . |
$$ . . O . . . . X . . |
$$ . . . . . . . . . . |
Click Here To Show Diagram Code
[go]$$W $$ --------------------- $$ . . . . X . . . . . | $$ . . . X X X O O 1 . | $$ . . O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]
For example:
$$W
$$ ---------------------
$$ . . 7 . X . 5 . 4 . |
$$ . . 3 X X X O O 1 2 |
$$ . . O O X O O X X 6 |
$$ , . . . O X X . . . |
$$ . . O . . . . X . . |
$$ . . . . . . . . . . |
Click Here To Show Diagram Code
[go]$$W $$ --------------------- $$ . . 7 . X . 5 . 4 . | $$ . . 3 X X X O O 1 2 | $$ . . O O X O O X X 6 | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]
Or:
$$W
$$ ---------------------
$$ . . . . X . . . . . |
$$ . . 2 X X X O O 1 . |
$$ . . O O X O O X X . |
$$ , . . . O X X . . . |
$$ . . O . . . . X . . |
$$ . . . . . . . . . . |
Click Here To Show Diagram Code
[go]$$W $$ --------------------- $$ . . . . X . . . . . | $$ . . 2 X X X O O 1 . | $$ . . O O X O O X X . | $$ , . . . O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]
There are a few variations.

If the original position has an extra black stone ,
it would simplify things -- I wonder if it's OK --
$$W
$$ ---------------------
$$ . . . . . . . . . . |
$$ . . . . 1 . . O B . |
$$ . . O . X O O X X . |
$$ , . . . . X X . . . |
$$ . . O . . . . X . . |
$$ . . . . . . . . . . |
Click Here To Show Diagram Code
[go]$$W $$ --------------------- $$ . . . . . . . . . . | $$ . . . . 1 . . O B . | $$ . . O . X O O X X . | $$ , . . . . X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]
sigger wrote:I'm still pretty new to the game, so I imagine it is fairly obvious,
sigger, this is not an obvious position for beginners,
especially with the original Diagram in post 1.

Posted: **Mon Mar 21, 2016 7:35 am**

Uberdude wrote:So I suppose a possible exercise is: can you construct a position in which that white counter atari does work to thwart black's plan?

With impeccable timing John Fairbairn has posted an old pro game with this shape, look at the game in this post, move 44: http://www.lifein19x19.com/forum/viewto ... 07#p201207.

Posted: **Mon Mar 21, 2016 7:55 am**

Uberdude wrote:
sigger wrote: What I'm wondering is why white can't atari with six instead of capturing, as in the second diagram.
Well done for considering a white resistance.

Hear, hear!

Posted: **Mon Mar 21, 2016 12:59 pm**

Thank you everyone for your help. I can see now specifically that I did not consider 4 in this position shown in schawipp's diagram:

Click Here To Show Diagram Code: [go]$$W $$ --------------------- $$ . . . . X . . . . . | $$ T 3 2 X X X O O 1 . | $$ . 4 O O X O O X X . | $$ , . . T O X X . . . | $$ . . O . . . . X . . | $$ . . . . . . . . . . |[/go]

In fact I think it would have been a loooong time before I considered it. So thank you again.

Life In 19x19

Shortage of liberties question

Shortage of liberties question

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