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tsumego #37

Posted: Mon Dec 10, 2012 5:47 pm
by cyclops
Day #37 December 11th
5 yrs ago no solutions to the advanced problem were posted. Maybe because the issues with the previous series. So solve it this time on your own risk as in real life.
#37a Advanced problem
Click Here To Show Diagram Code
[go]$$BC
$$-----------
$$|.X........
$$|OOOOOX.X..
$$|OXXOXX....
$$|X.XXOO.XX,
$$|.XXOX.OO..
$$|...O......
$$|.O.O.O....
$$|..........[/go]

#37b Intermediate problem
Click Here To Show Diagram Code
[go]$$BC
$$-----------
$$|.....OX...
$$|OOO.OOX.X.
$$|.X...OX...
$$|.XXXXX...,
$$|..........[/go]

#37c Elementary problem
Click Here To Show Diagram Code
[go]$$BC
$$--------
$$|XO.OX..
$$|X.XXXO.
$$|..OOOO.
$$|OO.,...
$$|.......[/go]

edit: Hi MagicWand, you are welcome to take over. If you get more responses than this one I withdraw happily.

Re: tsumego #37

Posted: Mon Dec 10, 2012 5:57 pm
by Josh Hatch
The closest I can find for black is a direct ko.
#37a Advanced problem
Click Here To Show Diagram Code
[go]$$Bc
$$-----------
$$|.X753.....
$$|OOOOOX.X..
$$|OXXOXX....
$$|X.XXOO.XX,
$$|6XXOX.OO..
$$|21.O......
$$|4O.O.O....
$$|..........[/go]

#37b Intermediate problem
Click Here To Show Diagram Code
[go]$$Bc 7 at 1
$$-----------
$$|..436OX...
$$|OOO1OOX.X.
$$|.X52.OX...
$$|.XXXXX...,
$$|..........[/go]

Note: 5 to the right of 2 would fail because after 6 and the throw in at 7 white connects at 5
Click Here To Show Diagram Code
[go]$$Bc 7 at 1, 9 at 3, 10 to the right of 1
$$-----------
$$|..436OX...
$$|OOO1OOX.X.
$$|.X825OX...
$$|.XXXXX...,
$$|..........[/go]

#37c Elementary problem
Click Here To Show Diagram Code
[go]$$Bc
$$--------
$$|XO.OX..
$$|X1XXXO.
$$|..OOOO.
$$|OO.,...
$$|.......[/go]

Re: tsumego #37

Posted: Fri Jan 11, 2013 7:52 am
by pancake
This ko is better for black. If white takes the ko and black takes the two stones, white still has to connect. In the other ko, white connected, then black took 2 stones.

Click Here To Show Diagram Code
[go]$$BC
$$-----------
$$|.X.53.....
$$|OOOOOX.X..
$$|OXXOXX....
$$|X.XXOO7XX,
$$|6XXOX.OO..
$$|12.O......
$$|4O.O.O....
$$|..........[/go]

Re: tsumego #37

Posted: Fri Jan 11, 2013 5:03 pm
by Prodigious
Here's an unconditional solution

Click Here To Show Diagram Code
[go]$$BC
$$-----------
$$|.X..9.....
$$|OOOOOX.X..
$$|OXXOXX....
$$|X.XXOO.XX,
$$|.XXOX.OO..
$$|564O......
$$|7O1O.O....
$$|.32.......
$$|.8........[/go]

Re: tsumego #37

Posted: Sat Jan 12, 2013 6:12 pm
by cyclops
Prodigious wrote:Here's an unconditional solution .........

Wow. you make me happy.
OC I tried to refute your solution but the next variant for :w2: fails.
Click Here To Show Diagram Code
[go]$$Bc a&b are miai for B after this sequence
$$ +---------------------
$$ | . X . . . . . . . .
$$ | O O O O O X . X . .
$$ | O X X O X X . . . .
$$ | X . X X O O . X X ,
$$ | . X X O B . O O . .
$$ | . 2 3 O . . . . . .
$$ | . O 1 O b O . . . .
$$ | . a 4 5 . . . . . .
$$ | . . . . . . . . . .[/go]

That is why the marked B stone is essential