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Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 3:04 pm
by SmoothOper
I wonder if any one has solved the fewest stones to break all ladders problem. This is probably pretty vague, maybe just any ladder from the third or forth line going inwards. I am thinking sort of analogously to the queens problem, placing 8 queens such that they weren't mutually attacking.
Re: Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 3:06 pm
by mitsun
Useful factoid: san-ren-sei (three star points) breaks all ladders.
Re: Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 3:10 pm
by HermanHiddema
mitsun wrote:Useful factoid: san-ren-sei (three star points) breaks all ladders.
Yes. The handicap points are exactly at the maximum distance from each other so that they break all ladders. If the space between them were one wider, a ladder could pass though the gap.
Therefore, 8 stones on the corner and side star points break all ladders going up from anywhere.
Note that the stones need to be on the fourth line for this to work. On the third line:
$$W White can bend the ladder at the last moment.
$$ ----------------------+
$$ . . . . . . . . . . . |
$$ . . . . O X 1 . . . . |
$$ . # . O X X O # . . . |
$$ . , O X X O . , . . . |
$$ . . . O O . . . . . . |
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- Click Here To Show Diagram Code
[go]$$W White can bend the ladder at the last moment.
$$ ----------------------+
$$ . . . . . . . . . . . |
$$ . . . . O X 1 . . . . |
$$ . # . O X X O # . . . |
$$ . , O X X O . , . . . |
$$ . . . O O . . . . . . |
$$ . . . . . . . . . . . |
$$ . . . . . . . . . . . |
$$ . . . . . . . . . . . |[/go]
Re: Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 3:17 pm
by SmoothOper
mitsun wrote:Useful factoid: san-ren-sei (three star points) breaks all ladders.
breaks all ladders going one direction.
Re: Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 4:52 pm
by DrStraw
So an 8 stone handicap breaks all ladders? If W plays tengen first does that enable them all?
Re: Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 9:24 pm
by Solomon
$$c
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- Click Here To Show Diagram Code
[go]$$c
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$$ ---------------------------------------[/go]
Re: Fewest stones needed to break all ladders
Posted: Wed Dec 11, 2013 10:14 pm
by Bill Spight
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 3:07 am
by ez4u
Probably we can all agree the first diagram is a ladder. If so, we can't use stones on the third line....
$$Wc A Ladder
$$+ - - - - - -
$$| . 2 3 . . .
$$| 1 X O . . .
$$| . O X . X .
$$| . . . , . .
$$| . . X . . .
$$| . . . . . .
- Click Here To Show Diagram Code
[go]$$Wc A Ladder
$$+ - - - - - -
$$| . 2 3 . . .
$$| 1 X O . . .
$$| . O X . X .
$$| . . . , . .
$$| . . X . . .
$$| . . . . . .[/go]
If the next diagram is also a 'ladder' we can't use the 3-2 point.
$$Wc A Ladder?
$$+ - - - - - -
$$| 2 3 . . . .
$$| X 1 X . X .
$$| O . . . . .
$$| . X . , . .
$$| . . . . . .
$$| . X . . . .
- Click Here To Show Diagram Code
[go]$$Wc A Ladder?
$$+ - - - - - -
$$| 2 3 . . . .
$$| X 1 X . X .
$$| O . . . . .
$$| . X . , . .
$$| . . . . . .
$$| . X . . . .[/go]
However, it seems to my eye that filling the second row with alternate stones as below will break all ladders. This requires four rows of eight stones or 32 stones in total.
$$Bc All Ladders Broken?
$$+ - - - - - -
$$| . . . . . .
$$| . X . X . X
$$| . . . . . .
$$| . X . , . .
$$| . . . . . .
$$| . X . . . .
- Click Here To Show Diagram Code
[go]$$Bc All Ladders Broken?
$$+ - - - - - -
$$| . . . . . .
$$| . X . X . X
$$| . . . . . .
$$| . X . , . .
$$| . . . . . .
$$| . X . . . .[/go]
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 6:48 am
by Bill Spight
$$Wc All Ladders Broken?
$$+ - - - - - -
$$| . . . . . .
$$| . X O X 1 X
$$| . . . O . .
$$| . X . , . .
$$| . . . . . .
$$| . X . . . .
- Click Here To Show Diagram Code
[go]$$Wc All Ladders Broken?
$$+ - - - - - -
$$| . . . . . .
$$| . X O X 1 X
$$| . . . O . .
$$| . X . , . .
$$| . . . . . .
$$| . X . . . .[/go]
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 7:10 am
by ez4u
So where do we go from here?
$$Wc All Ladders Broken?
$$+ - - - - - -
$$| . O X 1 X .
$$| . X O . . .
$$| X . . . . .
$$| . . . , . .
$$| X . . . . .
$$| . . . . . .
- Click Here To Show Diagram Code
[go]$$Wc All Ladders Broken?
$$+ - - - - - -
$$| . O X 1 X .
$$| . X O . . .
$$| X . . . . .
$$| . . . , . .
$$| X . . . . .
$$| . . . . . .[/go]
I'm assuming a rather different idea about the role of ladder breakers.
Edit: OK, I think I see your point, mine isn't a ladder. So we can't really get away from the first line?
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 7:25 am
by SmoothOper
I was thinking about posing a subtly different question. What placement of stones gives maximal ladder breakage for X stones. The easy case I think would be for one stone, at tengen. Two stones? Three stones etc.
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 7:37 am
by hyperpape
We could consider some kind of minimal ladders, for instance a bend, block, bend pattern.
$$Wc A Minimal Ladder?
$$+ - - - - - -
$$| . . O . . .
$$| . O B . . .
$$| O X B W . .
$$| O X O . . .
$$| . O . . . .
$$| . . . . . .
- Click Here To Show Diagram Code
[go]$$Wc A Minimal Ladder?
$$+ - - - - - -
$$| . . O . . .
$$| . O B . . .
$$| O X B W . .
$$| O X O . . .
$$| . O . . . .
$$| . . . . . .[/go]
I'm not saying that's the "true" meaning of ladder or anything like that. But it might be an interesting question, and perhaps we can avoid having to put as many stones on the board as Bill had to

Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 8:36 am
by SmoothOper
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$$ {LN D19 T4}
$$ {LN A16 Q1}
$$ {LN Q19 A4}
$$ {LN T16 D1}
- Click Here To Show Diagram Code
[go]$$c
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$$ ---------------------------------------
$$ {LN D19 T4}
$$ {LN A16 Q1}
$$ {LN Q19 A4}
$$ {LN T16 D1}[/go]
$$c
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$$ ---------------------------------------
$$ {LN A1 T19}
$$ {LN A7 N19}
$$ {LN T13 G1}
$$ {LN A19 T1}
$$ {LN A13 N1}
$$ {LN G19 T7}
- Click Here To Show Diagram Code
[go]$$c
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$$ ---------------------------------------
$$ {LN A1 T19}
$$ {LN A7 N19}
$$ {LN T13 G1}
$$ {LN A19 T1}
$$ {LN A13 N1}
$$ {LN G19 T7}[/go]
For more stones I think directionality and edge cases might come into play, as well as overlap.
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 10:36 am
by SmoothOper
Here is a configuration for three with minimum overlap, I would have to count to figure out the optimum centering.
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$$ ---------------------------------------
$$ {LN A2 S19}
$$ {LN A8 M19}
$$ {LN A16 Q1}
$$ {LN D19 T4}
$$ {LN A10 K1}
$$ {LN K19 T10}
$$ {LN A14 F19}
$$ {LN F1 T14}
- Click Here To Show Diagram Code
[go]$$c
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$$ ---------------------------------------
$$ {LN A2 S19}
$$ {LN A8 M19}
$$ {LN A16 Q1}
$$ {LN D19 T4}
$$ {LN A10 K1}
$$ {LN K19 T10}
$$ {LN A14 F19}
$$ {LN F1 T14}[/go]
Re: Fewest stones needed to break all ladders
Posted: Fri Dec 13, 2013 10:49 am
by SmoothOper
$$c
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$$ ---------------------------------------
$$ {LN A1 T19}
$$ {LN A7 N19}
$$ {LN A13 N1}
$$ {LN A19 T1}
$$ {LN A7 G1}
$$ {LN G19 T7}
$$ {LN A13 G19}
$$ {LN G1 T13}
$$ {LN N19 T13}
$$ {LN N1 T7}
- Click Here To Show Diagram Code
[go]$$c
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$$ ---------------------------------------
$$ {LN A1 T19}
$$ {LN A7 N19}
$$ {LN A13 N1}
$$ {LN A19 T1}
$$ {LN A7 G1}
$$ {LN G19 T7}
$$ {LN A13 G19}
$$ {LN G1 T13}
$$ {LN N19 T13}
$$ {LN N1 T7}[/go]
There that is better. Every position is covered for ladders in some direction, a majority of the board is covered in two directions. I suspect tengen would work its way back into the picture at five stones and triple directional coverage.