Which do you think is better:
- directly qualify number 1 and 2 and pair 3 vs. 4 or
pair all the players and qualify better loser by tie breaker?
It is not a real event (yet). We have a qualification tournament for the Finnish Championship league. 16 players play four rounds and the winer qualifies directly. Others play a fifth round and two more player with four wins qualify. Now there is a small chance that we do not get the 16 players and I was thinking what to do then.Javaness2 wrote:What a strange tournament! Is this a real event?
It is more complex.What does entry order mean? Is it an initial ranking of players based on their rating?
The rematch is only allowed to avoid pairing someone down.As a rematch is allowed in the rules, I think that the rematch option should be chosen.
However, I find it really strange that a rematch is allowed.
In this case yes.Elom wrote:I presume that only three players can qualify.
In the game 1 vs 4 player1 has (almost) nothing at stake. If he loses, he will anyway get the 3rd place by tie breaker.In method one, two players get a bye. In method two, full use is made of the extra round and qualification must still be earned by all players.
Pushing an equal effort requirement for qualification as far into the tournament as possible seems fairer to me, so I would choose option two, but pair 1 against 4 and 2 against 3.
What if you go by losses instead of wins? OC, byes favor certain players, but there you are. Counting byes as players, and eliminating actual players with 2 losses, we have this.Matti wrote:We have a qualification tournament for the Finnish Championship league. 16 players play four rounds and the winer qualifies directly. Others play a fifth round and two more player with four wins qualify. Now there is a small chance that we do not get the 16 players and I was thinking what to do then.