The "no ban in double ko" rule to solve pass-for-ko issue ?

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Gérard TAILLE
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by Gérard TAILLE »

kvasir wrote:
Click Here To Show Diagram Code
[go]$$B
$$ -------------------
$$ | O O X . X X O . .
$$ | O O O X . X O . .
$$ | X O O O X O O . .
$$ | . X O . X X O . .
$$ | X . X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
This position demonstrates how dangerous it is to try to pick a winning side in ko fights for the purpose of status confirmation.

One question I have that pertains to this position is how many pass-ko bans do we really need for each player? In this position black is dead because white can create two pass-ko bans in time to fill blacks last two liberties. Is it really needed to allow multiple pass-ko bans on the same player to achieve the desired effect? For example if white had to pick which ko had a pass-ko ban (that is one or the other ko stone would not be subject to a pass-ko), that would solve this position. That is if a player is allowed only one pass-ko ban at a time, could that work? If not, how many pass-ko bans do we really need?
Click Here To Show Diagram Code
[go]$$B
$$ ---------------------
$$ | . . . X O X . X . |
$$ | . . . X O O X X X |
$$ | . . . X O . O X O |
$$ | . . . X O O O O . |
$$ | . . . X X X X O O |
$$ | . . . . . . X X X |
$$ | X X X X . . . . . |
$$ | O O O X X . . . . |
$$ | . O . O X . . . . |
$$ ---------------------[/go]
Could you explain your proposal on the mooshine life position?
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by kvasir »

It is exactly the same as example 11 because the normal ko rule prevents white from taking again in the double-ko.
Click Here To Show Diagram Code
[go]$$B :w4: pass for :b1:
$$ ---------------------
$$ | . . . X O X 2 X . |
$$ | . . . X O O X X X |
$$ | . . . X O . O X O |
$$ | . . . X O O O O 3 |
$$ | . . . X X X X O O |
$$ | . . . . . . X X X |
$$ | X X X X . . . . . |
$$ | O O O X X . . . . |
$$ | 5 O 1 O X . . . . |
$$ ---------------------[/go]

No one really knows why example 11 has white pass for :b1: instead of :b3: and not create the pass-ko cycle in the double-ko. You will need another explanation of this (as you are actually working on) but maybe some of the tricky cases could be handled by limiting the number of pass-ko bans? I did not mean to put this up against some method to treat the double-ko cycle (that some believe doesn't exists for some reason) but to avoid using ko shapes to play multiple approach moves during status confirmation.

Example 7-2 (a bent-4 vs. 10'000 year ko) also works fine because again there is a point when two ko bans are needed buy one is provided with the normal ko rule.

I do not quite see why one needs to allow multiple pass-ko bans to get "Japanese" results. Obviously, there are different results in positions when one side could otherwise use pass-ko to play multiple moves in a row but that is not really bread and butter "Japanese" approach is it? Maybe there is some position someone came up with? But (by potentially fault intuition) I'd suggest that positions that require multiple pass-ko bans are quite in a flux, having more than one possible ko fight at once.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by Gérard TAILLE »

kvasir wrote:It is exactly the same as example 11 because the normal ko rule prevents white from taking again in the double-ko.

No one really knows why example 11 has white pass for :b1: instead of :b3: and not create the pass-ko cycle in the double-ko. You will need another explanation of this (as you are actually working on) but maybe some of the tricky cases could be handled by limiting the number of pass-ko bans? I did not mean to put this up against some method to treat the double-ko cycle (that some believe doesn't exists for some reason) but to avoid using ko shapes to play multiple approach moves during status confirmation.

Example 7-2 (a bent-4 vs. 10'000 year ko) also works fine because again there is a point when two ko bans are needed buy one is provided with the normal ko rule.

I do not quite see why one needs to allow multiple pass-ko bans to get "Japanese" results. Obviously, there are different results in positions when one side could otherwise use pass-ko to play multiple moves in a row but that is not really bread and butter "Japanese" approach is it? Maybe there is some position someone came up with? But (by potentially fault intuition) I'd suggest that positions that require multiple pass-ko bans are quite in a flux, having more than one possible ko fight at once.
Click Here To Show Diagram Code
[go]$$B
$$ ---------------------
$$ | . . . X O X 2 X . |
$$ | . . . X O O X X X |
$$ | . . . X O . O X O |
$$ | . . . X O O O O 3 |
$$ | . . . X X X X O O |
$$ | . . . . . . X X X |
$$ | X X X X . . . . . |
$$ | O O O X X . . . . |
$$ | . O 1 O X . . . . |
$$ ---------------------[/go]
The position reached is the following:
Click Here To Show Diagram Code
[go]$$B
$$ ---------------------
$$ | . . . X O M O X . |
$$ | . . . X O O X X X |
$$ | . . . X O . O X M |
$$ | . . . X O O O O X |
$$ | . . . X X X X O O |
$$ | . . . . . . X X X |
$$ | X X X X . . . . . |
$$ | O O O X X . . . . |
$$ | . O X M X . . . . |
$$ ---------------------[/go]
In this position black has created two pass-for-ko ban => is white allowed to retake the ko at the bottom?

Compare with the following position:
Click Here To Show Diagram Code
[go]$$B
$$ -------------------
$$ | . O X . X X O . .
$$ | O O O X . X O . .
$$ | X O O O X O O . .
$$ | . X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X 1 X X O . .
$$ | O O O X 2 X O . .
$$ | X O O O X O O . .
$$ | 3 X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O M O X X O . .
$$ | O O O X X X O . .
$$ | M O O O X O O . .
$$ | O X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
and white has created two pass-for-ko ban => is black allowed to retake the ko at the top?
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by kvasir »

Click Here To Show Diagram Code
[go]$$B
$$ ---------------------
$$ | . . . X O X 2 X . |
$$ | . . . X O O X X X |
$$ | . . . X O . O X O |
$$ | . . . X O O O O 3 |
$$ | . . . X X X X O O |
$$ | . . . . . . X X X |
$$ | X X X X . . . . . |
$$ | O O O X X . . . . |
$$ | . O 1 O X . . . . |
$$ ---------------------[/go]
White is not allowed to take at the bottom because black chooses to protect there with the pass-ko, likewise white is not allowed to take in the double-ko because of the regular ko rule. There is no difference because black only needs to protect one ko using pass-ko (hypothetically because there is the pass-ko double-ko cycle anyway).


Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O M O X X O . .
$$ | O O O X X X O . .
$$ | M O O O X O O . .
$$ | O X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
It would be up to white which ko to protect with pass-ko, but he could not protect both if the number of active pass-ko bans was limited to one per player at time. The position is symmetric so white just picks either one and black then takes the other ko.

Please come up with something to challenge this if I was able to explain what I meant :D What I am trying to say is that if each player is allowed to protect one ko at a time using pass-ko it seems to work with all the J89 examples and rule out some forms of pass-ko abuse (for lack of a neutral phrase). It is also similar to pass-once but doesn't preclude using the pass-ko rule repeatedly in the same shape.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by Gérard TAILLE »

kvasir wrote:
Click Here To Show Diagram Code
[go]$$B
$$ ---------------------
$$ | . . . X O X 2 X . |
$$ | . . . X O O X X X |
$$ | . . . X O . O X O |
$$ | . . . X O O O O 3 |
$$ | . . . X X X X O O |
$$ | . . . . . . X X X |
$$ | X X X X . . . . . |
$$ | O O O X X . . . . |
$$ | . O 1 O X . . . . |
$$ ---------------------[/go]
White is not allowed to take at the bottom because black chooses to protect there with the pass-ko, likewise white is not allowed to take in the double-ko because of the regular ko rule. There is no difference because black only needs to protect one ko using pass-ko (hypothetically because there is the pass-ko double-ko cycle anyway).


Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O M O X X O . .
$$ | O O O X X X O . .
$$ | M O O O X O O . .
$$ | O X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
It would be up to white which ko to protect with pass-ko, but he could not protect both if the number of active pass-ko bans was limited to one per player at time. The position is symmetric so white just picks either one and black then takes the other ko.
I do not understand. As in the previous example white can choose simply to protect the ko at the top and the other ko is protected by regular ko. What is the difference?
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by kvasir »

Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X 3 X X O . .
$$ | O O O X 4 X O . .
$$ | X O O O X O O . .
$$ | 1 X O 5 X X O . .
$$ | X 2 X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
There is no regular ko ban in this position, only the pass-ko bans. If white can only have a single pass-ko ban at a time then black could take back in one of the kos without first passing. That is the difference.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by Gérard TAILLE »

kvasir wrote:
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X 3 X X O . .
$$ | O O O X 4 X O . .
$$ | X O O O X O O . .
$$ | 1 X O 5 X X O . .
$$ | X 2 X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
There is no regular ko ban in this position, only the pass-ko bans. If white can only have a single pass-ko ban at a time then black could take back in one of the kos without first passing. That is the difference.
Oh I see where is the misunderstanding. The position I proposed is not that one above but the following:
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X . X X O . .
$$ | O O O X . X O . .
$$ | X O O O X O O . .
$$ | . X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X 1 X X O . .
$$ | O O O X 2 X O . .
$$ | X O O O X O O . .
$$ | 3 X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by kvasir »

Gérard TAILLE wrote:
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X 1 X X O . .
$$ | O O O X 2 X O . .
$$ | X O O O X O O . .
$$ | 3 X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
That is a different position and white would be able to use the pass-ko and the regular ko ban to demonstrate the black group is dead. The result would then be a seki. This is exactly same as with regular pass-ko rule because you still have two ko bans.


You could create a position like this to get different results.
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X . X X O . .
$$ | O O O X . X O . .
$$ | O O O X X O O .
$$ | O O X . X X O . .
$$ | O O O X . X O . .
$$ | X O O O X O O . .
$$ | . X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
Click Here To Show Diagram Code
[go]$$W
$$ -------------------
$$ | . O X 1 X X O . .
$$ | O O O X 2 X O . .
$$ | O O O X X O O .
$$ | O O X 3 X X O . .
$$ | O O O X 4 X O . .
$$ | X O O O X O O . .
$$ | 5 X O O X X O . .
$$ | X X X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
Is it desirable or undesirable to let white claim there are three ko bans now? I'd say it is undesirable, and I find it hard to imagine a position when we want one side to defend SIMULTANIOUSLY in more than two kos. Such things may exist but the examples in j89 don't require it.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by Gérard TAILLE »

kvasir wrote:
Click Here To Show Diagram Code
[go]$$B
$$ -------------------
$$ | O O X . X X O . .
$$ | O O O X . X O . .
$$ | X O O O X O O . .
$$ | . X O . X X O . .
$$ | X . X X . X O . .
$$ | X X O X X X O . .
$$ | O O O O O O O . .
$$ | . . . . . . . . .
$$ | . . . . . . . . .[/go]
This position demonstrates how dangerous it is to try to pick a winning side in ko fights for the purpose of status confirmation.

One question I have that pertains to this position is how many pass-ko bans do we really need for each player? In this position black is dead because white can create two pass-ko bans in time to fill blacks last two liberties. Is it really needed to allow multiple pass-ko bans on the same player to achieve the desired effect? For example if white had to pick which ko had a pass-ko ban (that is one or the other ko stone would not be subject to a pass-ko), that would solve this position. That is if a player is allowed only one pass-ko ban at a time, could that work? If not, how many pass-ko bans do we really need?
I think now your are right Jann. I am not able to find an example in which one player need more than one pass-ko ban. Good point indeed.

Coming back to my proposal with the "no ban in double ko" rule the point is that in some double ko situations even a single pass-ko ban is an issue:
Click Here To Show Diagram Code
[go]$$B
$$ -------------------------------
$$ | O . O . X X . . O . . O X . .
$$ | O O O X O X X O O O O O X . .
$$ | X X X O . O O O X X X X X . .
$$ | . . X O O O X X X . . . . . .
$$ | . . X X X X X . . . . . . . .
$$ | . . . . . . . . . . . . . . .
$$ | . . . . . . . . . . . . . . .[/go]
Click Here To Show Diagram Code
[go]$$B
$$ -------------------------------
$$ | O . O . X X 2 3 O . . O X . .
$$ | O O O X O X X O O O O O X . .
$$ | X X X O 1 O O O X X X X X . .
$$ | . . X O O O X X X . . . . . .
$$ | . . X X X X X . . . . . . . .
$$ | . . . . . . . . . . . . . . .
$$ | . . . . . . . . . . . . . . .[/go]
and white can neither retake the ko at :b1: (pass-ko ban) nor the ko at :b3: (regular ko).
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by jann »

Gérard TAILLE wrote:
kvasir wrote:That is if a player is allowed only one pass-ko ban at a time, could that work? If not, how many pass-ko bans do we really need?
I think now your are right Jann. I am not able to find an example in which one player need more than one pass-ko ban.
That was not my quote, I still think the left-or-right examples from the other topic show why one pass-ko ban is not enough - IF Japanese-style results (no ko interaction) are desired.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by Gérard TAILLE »

jann wrote:
Gérard TAILLE wrote:
kvasir wrote:That is if a player is allowed only one pass-ko ban at a time, could that work? If not, how many pass-ko bans do we really need?
I think now your are right Jann. I am not able to find an example in which one player need more than one pass-ko ban.
That was not my quote, I still think the left-or-right examples from the other topic show why one pass-ko ban is not enough - IF Japanese-style results (no ko interaction) are desired.
Yes I agree Jann. In this thread I only consider positions with double ko and in this context and in Japanese-style rule your comment was to me quite interesting.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by kvasir »

jann wrote:
Gérard TAILLE wrote:
kvasir wrote:That is if a player is allowed only one pass-ko ban at a time, could that work? If not, how many pass-ko bans do we really need?
I think now your are right Jann. I am not able to find an example in which one player need more than one pass-ko ban.
That was not my quote, I still think the left-or-right examples from the other topic show why one pass-ko ban is not enough - IF Japanese-style results (no ko interaction) are desired.
I don't get what interactions in you mean in that specific position, Jann. I think I treated the position incorrectly before, it is a bit tricky to have a pass-ko and a regular ko ban, now I don't think there is any difference from regular pass-ko in this case because of how black takes the kos first. Because black takes the kos first he will have a regular ko ban in one and a pass-ko ban in the other, allowing black to capture everything.

It is basically the same as your pass-once except that possibility of reusing the pass-ko ban is not discarded AND it solves the issue of allowing use of pass-ko to force multiple moves in a row in at least some positions. Like with any change or interpretation of anything in J89 there will be different results in some positions (that is the intention) but it does appear to work with all of the examples.

Anyway, I don't expect it to work 100%. For one thing J89 still has unclear "enable", a double-ko cycles, and a lofty idea of a "Japanese" understanding of what is the correct result. It is too subjective to really match everyone's idea of what 100% is. I am more interested in understanding the benefits and limitations.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by jann »

kvasir wrote:I don't get what interactions in you mean in that specific position, Jann. I think I treated the position incorrectly before, it is a bit tricky to have a pass-ko and a regular ko ban, now I don't think there is any difference from regular pass-ko in this case because of how black takes the kos first. Because black takes the kos first he will have a regular ko ban in one and a pass-ko ban in the other, allowing black to capture everything.
Click Here To Show Diagram Code
[go]$$B
$$ +---------------
$$ | X X . P P X . O O Z Z . |
$$ | X P P P X X O O O Z O O |
$$ | . P X X . X O . O Z Z O |
$$ | P P X X X X O O O Z . . |
$$ --------------------
$$[/go]
I thought that: B starts the bent4 ko and takes it first, W throws in at right, B captures there as well. At this point (if there is only one pass-ko ban) W passes for whichever of the two kos B chooses to have protected. Next B resolves one of the kos and W captures in the other, thus saving central stones and even bent4 will be alive (directly or on enabling). Right?
For one thing J89 still has unclear "enable", a double-ko cycles, and a lofty idea of a "Japanese" understanding of what is the correct result.
Hmm, I think J89 is actually not bad (if you accept its approach to ko), better than I thought in the past.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by kvasir »

This is my current thought of how the position goes when black tries to capture in confirmation.
Click Here To Show Diagram Code
[go]$$B
$$ +---------------
$$ | . X . O O X . O O X X . |
$$ | 1 O O O X X O O O X O O |
$$ | O O X X . X O . O X X O |
$$ | O O X X X X O O O X 2 3 |
$$ --------------------
$$[/go]
Black protects :b1: with pass-ko, the other ko will be protected by the regular ko rule.

White passes for :w2: because he can take in neither ko shape, one protected by pass-ko and the other by regular ko rule.

:b5: finishes the ko that was protected by the regular ko rule. (There may be an ambiguity about if you are allowed to switch the pass-ko ban around but we don't need it here).

White still can't take in the bent-4 because of the pass-ko ban, black takes there also with :b7:.
Click Here To Show Diagram Code
[go]$$B
$$ +---------------
$$ | . X 7 O O X . O O X X 5 |
$$ | X O O O X X O O O X O O |
$$ | O O X X . X O . O X X O |
$$ | O O X X X X O O O X . X |
$$ --------------------
$$[/go]

So it appears that black only needs one pass-ko ban to capture everything in this position.
jann wrote:
For one thing J89 still has unclear "enable", a double-ko cycles, and a lofty idea of a "Japanese" understanding of what is the correct result.
Hmm, I think J89 is actually not bad (if you accept its approach to ko), better than I thought in the past.
I agree that J89 is not so bad. It is just that I think that we can't talk about perfection or treat its concepts formally all the time. The semantics of J89 are not always clear enough, but I do like how it presents a simple and elegant approach. I still doubt it really works except in practice (when we are really just happy to finish the game).

I'd also add that the faults in some other rule texts are lot more comical than J89, for one thing we tend to just ignore anything not doing with the position on the board. That is really a faulty approach but understandable because it is the position in the game that interests us.
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Re: The "no ban in double ko" rule to solve pass-for-ko issu

Post by jann »

kvasir wrote:Black protects :b1: with pass-ko, the other ko will be protected by the regular ko rule.

White passes for :w2: because he can take in neither ko shape, one protected by pass-ko and the other by regular ko rule.
I don't understand this. As I wrote I think W passes for the protected ko (B 1). What does it mean to pass for a ko that is not protected anyway?

Hm, maybe you mean passing for the ko itself is forbidden by the protection? But then how can such protection be eliminated? You need a way for that to prevent anomalies (or a different kind of double ko abuse).
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