I'll try to use these pages from senseis:
https://senseis.xmp.net/?MiaiCounting and
https://senseis.xmp.net/?MiaiCountingWithTrees
I put positions A, B and C in a tree, taking left branches as black moves and right branches as white moves (but I collapse some sequences).
$$W A
$$ ----------------------------
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . 1 O . . |
$$ . . . . . . . X O . X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |
- Click Here To Show Diagram Code
[go]$$W A
$$ ----------------------------
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . 1 O . . |
$$ . . . . . . . X O . X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |[/go]
$$W B: count = 2
$$ ----------------------------
$$ . . . . . T T 6 2 5 S S . |
$$ . . . . . T T 4 3 1 O . . |
$$ . . . . . . . X O . X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |
- Click Here To Show Diagram Code
[go]$$W B: count = 2
$$ ----------------------------
$$ . . . . . T T 6 2 5 S S . |
$$ . . . . . T T 4 3 1 O . . |
$$ . . . . . . . X O . X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |[/go]
$$W C: count = -5
$$ ----------------------------
$$ . . . . . 6 5 7 S S S S . |
$$ . . . . . 0 4 3 9 1 O S . |
$$ . . . . . . . X O 8 X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |
- Click Here To Show Diagram Code
[go]$$W C: count = -5
$$ ----------------------------
$$ . . . . . 6 5 7 S S S S . |
$$ . . . . . 0 4 3 9 1 O S . |
$$ . . . . . . . X O 8 X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |[/go]
Filling in counts:
Backtracking counts and calculating the temperature (between parentheses) of position A:
What I further understand from those pages:
If the ambient temperature < 3.5, black should respond locally like B (or an equivalent move) with count 2.
In that case we need to prune C from the move tree, so we get:
However, if the ambient temperature > 3.5, black should play a bigger move elsewhere, allowing white to move to C with count -5.
I also think the ambient temperature should not be too high (like >= 4.5), otherwise white should not even be playing in this area to begin with.
An alternative for position A is position D:
$$W D: count = 2
$$ ----------------------------
$$ . . . . . . . 1 . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . X O . X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |
- Click Here To Show Diagram Code
[go]$$W D: count = 2
$$ ----------------------------
$$ . . . . . . . 1 . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . X O . X O . |
$$ . . X , . X . X X X . O . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . O . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . . . . |
$$ . . . . . . . . . . O . . |
$$ . . . , . . . . . , . . . |[/go]
So it seems to me that D is equivalent to A when the ambient temperature <= 3.5.
But if 3.5 < ambient temperature < 4.5, is A better for white than D (because A would then have count -1.5)?
Edit: Changed 'miai count' to just 'count' after Robert Jasiek's remark about terminology below.