Here is a small problem. Although I composed it, I am quite sure someone else have composed it before. Enjoy!
$$B Status? $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O . . O . . O X . . $$ . . . O . . . . . O . . . $$ -------------------------
[go]$$B Status? $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O . . O . . O X . . $$ . . . O . . . . . O . . . $$ -------------------------[/go]
Nice problem - thanks The following is almost certainly wrong, but I like to have a go:
I think white is unconditionally alive. Black's strongest attempt seems to be the following, but white can resist:
$$B Status? $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O 2 1 O 4 . O X . . $$ . . 5 O a 3 6 . b O . . . $$ -------------------------
[go]$$B Status? $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O 2 1 O 4 . O X . . $$ . . 5 O a 3 6 . b O . . . $$ -------------------------[/go]
-- a and b are miai. If black plays 3 at 4, then white plays 4 at 3, sacrificing the two stones to live on the left.
I guess black might have stronger attempts that I have missed though. Playing on the point of symmetry does't seem to work - for example:
$$B Status? $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O 6 3 O . 5 O X . . $$ . . . O . 4 1 2 . O . . . $$ -------------------------
[go]$$B Status? $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O 6 3 O . 5 O X . . $$ . . . O . 4 1 2 . O . . . $$ -------------------------[/go]
It's a bit more complicated than it looks though. I await the SDKs and dan players to point out what I've missed
Hmm, I missed here until robinz pointed it out, and didn't understand why this could be considered a very difficult problem.
$$B $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O 2 1 O 4 . O X . . $$ . . . O . 3 . . . O . . . $$ -------------------------
[go]$$B $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O 2 1 O 4 . O X . . $$ . . . O . 3 . . . O . . . $$ -------------------------[/go]
However, I still think there is a solution that kills white:
$$B $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O O X O O . O X . . $$ . . . O . X 6 . 5 O 7 . . $$ -------------------------
[go]$$B $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O O X O O . O X . . $$ . . . O . X 6 . 5 O 7 . . $$ -------------------------[/go]
We don't know who we are; we don't know where we are.
Each of us woke up one moment and here we were in the darkness.
We're nameless things with no memory; no knowledge of what went before,
No understanding of what is now, no knowledge of what will be.
$$B All stones alive $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O . 2 O . . O X . . $$ . . . O . . 1 . . O . . . $$ -------------------------
[go]$$B All stones alive $$ . . . . . . . . . . . . . $$ . . X X X X X X X X X . . $$ . X . X O O X O O X . X . $$ . . X O . 2 O . . O X . . $$ . . . O . . 1 . . O . . . $$ -------------------------[/go]
@ Dusk Eagle:
I never said that this problem is going to be difficult.
The following is almost certainly wrong, but I like to have a go:
here until robinz pointed it out, and didn't understand why this could be considered a very difficult problem.