EDIT:
moved to physics thread
mosquito meets train
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Tommie
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mosquito meets train
Last edited by Tommie on Wed Nov 24, 2010 3:23 am, edited 1 time in total.
Greetings,
Tommie
3dan EGF (AGA no 13477) || Tommie on KGS: 'June'|| DGS: 'Zhi Laohu' 纸老虎 = 'paper tiger' || Senseis : http://senseis.xmp.net/?tderz ||
ENFP (MBTI) - 'Find your own style within the Fundamentals of Go! '
Tommie
3dan EGF (AGA no 13477) || Tommie on KGS: 'June'|| DGS: 'Zhi Laohu' 纸老虎 = 'paper tiger' || Senseis : http://senseis.xmp.net/?tderz ||
ENFP (MBTI) - 'Find your own style within the Fundamentals of Go! '
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Li Kao
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Re: mosquito meets train
The relative speed of insect and train was 0 for a moment (and since the body of the insect is likeley to stay on the train probably for longer).
The speed of the train relative to earth was never 0 during the incident.
The speed of the insect relative to earth might have been 0 during the incident. If the insect was moving in the same direction as the train before the impact the speed doesn't go to 0, if it was moving in the opposite direction of the train it goes to 0 very shortly. But since the insect gets deformed during that process defining its speed is a bit hard.
I have no clue what you want to say in your last paragraph.
m(Train)*v(Train)+m(Train)+v(insect) is constant at all times (disregarding friction)
The speed of the train relative to earth was never 0 during the incident.
The speed of the insect relative to earth might have been 0 during the incident. If the insect was moving in the same direction as the train before the impact the speed doesn't go to 0, if it was moving in the opposite direction of the train it goes to 0 very shortly. But since the insect gets deformed during that process defining its speed is a bit hard.
I have no clue what you want to say in your last paragraph.
m(Train)*v(Train)+m(Train)+v(insect) is constant at all times (disregarding friction)
Sanity is for the weak.