logan wrote:$$Bm33 BP:3 WP:0
$$ -------------------
$$ | . . . . . . . . . |
$$ | . . . Q . . 5 . . |
$$ | . . X X Q Q , . . |
$$ | . . . . X Q 1 3 . |
$$ | . . . . X X O O O |
$$ | . . X X . O X X O |
$$ | . . O X . O O X 2 |
$$ | . . . . O . X 4 X |
$$ | . . . . . . X X X |
$$ -------------------
- Click Here To Show Diagram Code
[go]$$Bm33 BP:3 WP:0
$$ -------------------
$$ | . . . . . . . . . |
$$ | . . . Q . . 5 . . |
$$ | . . X X Q Q , . . |
$$ | . . . . X Q 1 3 . |
$$ | . . . . X X O O O |
$$ | . . X X . O X X O |
$$ | . . O X . O O X 2 |
$$ | . . . . O . X 4 X |
$$ | . . . . . . X X X |
$$ -------------------[/go]
Black wins capture race.
...
Thanks, that's really interesting (for me at least

). That B wins the capturing race, was not obvious for me. I thought of some variations as the following:
$$Wm38 BP:3 WP:0
$$ -------------------
$$ | . . . . . . 8 7 . |
$$ | . . 4 O 3 . X 5 6 |
$$ | . . X X O O 1 2 . |
$$ | . . . . X O X X 9 |
$$ | . . . . X X O O O |
$$ | . . X X . O . . O |
$$ | . . O X . O O . O |
$$ | . . . . O . X O X |
$$ | . . . . . . X X X |
$$ -------------------
- Click Here To Show Diagram Code
[go]$$Wm38 BP:3 WP:0
$$ -------------------
$$ | . . . . . . 8 7 . |
$$ | . . 4 O 3 . X 5 6 |
$$ | . . X X O O 1 2 . |
$$ | . . . . X O X X 9 |
$$ | . . . . X X O O O |
$$ | . . X X . O . . O |
$$ | . . O X . O O . O |
$$ | . . . . O . X O X |
$$ | . . . . . . X X X |
$$ -------------------[/go]
$$Bm47 BP:3 WP:0
$$ -------------------
$$ | . . . . . . X 3 1 |
$$ | . . X O O . X 2 X |
$$ | . . X X O O O X 4 |
$$ | . . . . X O X X O |
$$ | . . . . X X O O O |
$$ | . . X X . O . . O |
$$ | . . O X . O O . O |
$$ | . . . . O . X O X |
$$ | . . . . . . X X X |
$$ -------------------
- Click Here To Show Diagram Code
[go]$$Bm47 BP:3 WP:0
$$ -------------------
$$ | . . . . . . X 3 1 |
$$ | . . X O O . X 2 X |
$$ | . . X X O O O X 4 |
$$ | . . . . X O X X O |
$$ | . . . . X X O O O |
$$ | . . X X . O . . O |
$$ | . . O X . O O . O |
$$ | . . . . O . X O X |
$$ | . . . . . . X X X |
$$ -------------------[/go]
And after the squeeze the B stones have only 2 liberties against 3 liberties left. Thinking against about it, a better way is obviously the following:
$$Wm38 BP:3 WP:0
$$ -------------------
$$ | . . . . . . . . . |
$$ | . . . O 3 . X 4 . |
$$ | . . X X O O 1 2 . |
$$ | . . . . X O X X . |
$$ | . . . . X X O O O |
$$ | . . X X . O . . O |
$$ | . . O X . O O . O |
$$ | . . . . O . X O X |
$$ | . . . . . . X X X |
$$ -------------------
- Click Here To Show Diagram Code
[go]$$Wm38 BP:3 WP:0
$$ -------------------
$$ | . . . . . . . . . |
$$ | . . . O 3 . X 4 . |
$$ | . . X X O O 1 2 . |
$$ | . . . . X O X X . |
$$ | . . . . X X O O O |
$$ | . . X X . O . . O |
$$ | . . O X . O O . O |
$$ | . . . . O . X O X |
$$ | . . . . . . X X X |
$$ -------------------[/go]
Here the B stones have 6 vs. 4 liberties which should be easy. Are there other possibilities than black-41? Thank you in advance for correction of any flaws (I am starting to get serious doubts about my reading capabilities...

).
Edit: If in my first diagram, B plays 43 at 44, this seems also a possible solution.
(I am starting to get serious doubts about my reading capabilities...

)
No further comments on that
